Database : Oracle 10g
Schema : Scott/Tiger
If you have a hiearchial table, the following generic query presents the data in a hierarchical form.
column graph format a10;
select rpad( '*', 2*level, '*' ) graph, level, t.*
from t
connect by prior p_node = c_node;
p_node = parent node
c_node = child node
If you want to get the hierarchy of a particular node, use "starts with".
Eg :
column graph format a10
select rpad( '*', 2*level, '*' ) graph, level, t.*
from t
start with c_node = '&node_number'
connect by prior p_node = c_node;
Let's take a look at the standard emp table on scott/tiger schema.
To see the full hierarchy in the table (employee -> Manager relationship), fire the following query :
select rpad( '*', 2*level, '*' ) graph, level, e.*
from emp e
connect by prior e.mgr = e.empno
order by deptno;
Let's start with an employee in a department and see what happens.
select rpad( '*', 2*level, '*' ) graph, level, e.*
from emp e
start with e.empno = 7934
connect by prior e.mgr = e.empno
order by deptno;
Long live "Tom kyte".
Good Luck,
r-a-v-i
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1 comment:
Good brief and this mail helped me alot in my college assignement. Thanks you for your information.
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